Solution :
==> 2*pi* r = 6600/15 =440m
==> r = 70m
Area = pi*r^2= 22/7 *70*70 = 15,400
Total cost = 15,400*50=7,70,000
Solution :
Total Weight of men = 20*72= 1440
Total Weight of women = 34*62.5 = 2125
Average weight of all men and women = (1440+2125)/(20+34) = 66.01~ = 66 kgs
Solution :
Ratio difference = 9-7=2 units
Age difference = 4
2 units ---------- 4
7 units --------- ?
Mark age = 14 years
Similarly Steve age = 18 years
Mark is twice as old as he is age = 14 +14 =28
At the same time Steve age = 18+14 = 32
New ratio = 7:8
Age difference = 4
2 units ---------- 4
7 units --------- ?
Mark age = 14 years
Similarly Steve age = 18 years
Mark is twice as old as he is age = 14 +14 =28
At the same time Steve age = 18+14 = 32
New ratio = 7:8
Solution :
L.C.M of 20,30 and 60 = 60 = Total work
A efficiency = 60/20 =3
B efficiency = 60/30 = 2
C efficiency = 60/60 = 1
A working 2 days and third day they all working together
So total efficiency = A efficiency + A efficiency + A , B and C efficiency ( for 3days )
==> 3+3+6=12
Work completed = 60/12 = 5
Total days = 5*3 = 15 days
Solution :
Speed * 10 --------- 36 sec ( its gives how many meters travelled in 36 sec)
Train speed = x kmph
Man speed = 2 kmph
Relative Speed = x-2
(X-2)*10 ----------- 36 sec
150. ----------- 3 sec
==> 30(x-2) = 5400
==> x = 182kmph
Solution :
Total distance = x km
==> (x/2)/21 + (x/2)/24 = 10
==> X = 224 km
Solution :
Case i :
If 15 persons are sent from X to Y, then the number of persons in each building is the same.
==> X-15 = Y +15
==> Y = X -30 ---- (i)
Case ii :
If 20 persons are sent from Y to X, then the number of persons in X is double the number of persons in Y.
==> X+20 = 2*(Y-20) ---- ii
Sub eq (i) in eq ii
==> X = 120
Solution :
Simple Interest (SI) for 1 year = 900-850=50
Simple Interest (SI) for 3 years = 50 × 3 = 150
Principal = 850 - 150= 700
Solution :
1/6 --------- 100%
1/x --------- 120%
X = 5
Solution :
Total time = (4864/(16)) + (4864/(12))
= 304 + 405.33 = 709.33 ~= 709 hrs
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